Integrand size = 16, antiderivative size = 124 \[ \int x^7 \left (a+b \arctan \left (c x^2\right )\right )^2 \, dx=\frac {a b x^2}{4 c^3}+\frac {b^2 x^4}{24 c^2}+\frac {b^2 x^2 \arctan \left (c x^2\right )}{4 c^3}-\frac {b x^6 \left (a+b \arctan \left (c x^2\right )\right )}{12 c}-\frac {\left (a+b \arctan \left (c x^2\right )\right )^2}{8 c^4}+\frac {1}{8} x^8 \left (a+b \arctan \left (c x^2\right )\right )^2-\frac {b^2 \log \left (1+c^2 x^4\right )}{6 c^4} \]
[Out]
Time = 0.18 (sec) , antiderivative size = 124, normalized size of antiderivative = 1.00, number of steps used = 12, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {4948, 4946, 5036, 272, 45, 4930, 266, 5004} \[ \int x^7 \left (a+b \arctan \left (c x^2\right )\right )^2 \, dx=-\frac {\left (a+b \arctan \left (c x^2\right )\right )^2}{8 c^4}+\frac {1}{8} x^8 \left (a+b \arctan \left (c x^2\right )\right )^2-\frac {b x^6 \left (a+b \arctan \left (c x^2\right )\right )}{12 c}+\frac {a b x^2}{4 c^3}+\frac {b^2 x^2 \arctan \left (c x^2\right )}{4 c^3}+\frac {b^2 x^4}{24 c^2}-\frac {b^2 \log \left (c^2 x^4+1\right )}{6 c^4} \]
[In]
[Out]
Rule 45
Rule 266
Rule 272
Rule 4930
Rule 4946
Rule 4948
Rule 5004
Rule 5036
Rubi steps \begin{align*} \text {integral}& = \frac {1}{2} \text {Subst}\left (\int x^3 (a+b \arctan (c x))^2 \, dx,x,x^2\right ) \\ & = \frac {1}{8} x^8 \left (a+b \arctan \left (c x^2\right )\right )^2-\frac {1}{4} (b c) \text {Subst}\left (\int \frac {x^4 (a+b \arctan (c x))}{1+c^2 x^2} \, dx,x,x^2\right ) \\ & = \frac {1}{8} x^8 \left (a+b \arctan \left (c x^2\right )\right )^2-\frac {b \text {Subst}\left (\int x^2 (a+b \arctan (c x)) \, dx,x,x^2\right )}{4 c}+\frac {b \text {Subst}\left (\int \frac {x^2 (a+b \arctan (c x))}{1+c^2 x^2} \, dx,x,x^2\right )}{4 c} \\ & = -\frac {b x^6 \left (a+b \arctan \left (c x^2\right )\right )}{12 c}+\frac {1}{8} x^8 \left (a+b \arctan \left (c x^2\right )\right )^2+\frac {1}{12} b^2 \text {Subst}\left (\int \frac {x^3}{1+c^2 x^2} \, dx,x,x^2\right )+\frac {b \text {Subst}\left (\int (a+b \arctan (c x)) \, dx,x,x^2\right )}{4 c^3}-\frac {b \text {Subst}\left (\int \frac {a+b \arctan (c x)}{1+c^2 x^2} \, dx,x,x^2\right )}{4 c^3} \\ & = \frac {a b x^2}{4 c^3}-\frac {b x^6 \left (a+b \arctan \left (c x^2\right )\right )}{12 c}-\frac {\left (a+b \arctan \left (c x^2\right )\right )^2}{8 c^4}+\frac {1}{8} x^8 \left (a+b \arctan \left (c x^2\right )\right )^2+\frac {1}{24} b^2 \text {Subst}\left (\int \frac {x}{1+c^2 x} \, dx,x,x^4\right )+\frac {b^2 \text {Subst}\left (\int \arctan (c x) \, dx,x,x^2\right )}{4 c^3} \\ & = \frac {a b x^2}{4 c^3}+\frac {b^2 x^2 \arctan \left (c x^2\right )}{4 c^3}-\frac {b x^6 \left (a+b \arctan \left (c x^2\right )\right )}{12 c}-\frac {\left (a+b \arctan \left (c x^2\right )\right )^2}{8 c^4}+\frac {1}{8} x^8 \left (a+b \arctan \left (c x^2\right )\right )^2+\frac {1}{24} b^2 \text {Subst}\left (\int \left (\frac {1}{c^2}-\frac {1}{c^2 \left (1+c^2 x\right )}\right ) \, dx,x,x^4\right )-\frac {b^2 \text {Subst}\left (\int \frac {x}{1+c^2 x^2} \, dx,x,x^2\right )}{4 c^2} \\ & = \frac {a b x^2}{4 c^3}+\frac {b^2 x^4}{24 c^2}+\frac {b^2 x^2 \arctan \left (c x^2\right )}{4 c^3}-\frac {b x^6 \left (a+b \arctan \left (c x^2\right )\right )}{12 c}-\frac {\left (a+b \arctan \left (c x^2\right )\right )^2}{8 c^4}+\frac {1}{8} x^8 \left (a+b \arctan \left (c x^2\right )\right )^2-\frac {b^2 \log \left (1+c^2 x^4\right )}{6 c^4} \\ \end{align*}
Time = 0.12 (sec) , antiderivative size = 121, normalized size of antiderivative = 0.98 \[ \int x^7 \left (a+b \arctan \left (c x^2\right )\right )^2 \, dx=\frac {c x^2 \left (6 a b+b^2 c x^2-2 a b c^2 x^4+3 a^2 c^3 x^6\right )-2 b \left (b c x^2 \left (-3+c^2 x^4\right )+a \left (3-3 c^4 x^8\right )\right ) \arctan \left (c x^2\right )+3 b^2 \left (-1+c^4 x^8\right ) \arctan \left (c x^2\right )^2-4 b^2 \log \left (1+c^2 x^4\right )}{24 c^4} \]
[In]
[Out]
Time = 0.86 (sec) , antiderivative size = 151, normalized size of antiderivative = 1.22
method | result | size |
default | \(\frac {a^{2} x^{8}}{8}+\frac {b^{2} x^{8} \arctan \left (c \,x^{2}\right )^{2}}{8}-\frac {b^{2} \arctan \left (c \,x^{2}\right ) x^{6}}{12 c}+\frac {b^{2} x^{2} \arctan \left (c \,x^{2}\right )}{4 c^{3}}-\frac {b^{2} \arctan \left (c \,x^{2}\right )^{2}}{8 c^{4}}+\frac {b^{2} x^{4}}{24 c^{2}}-\frac {b^{2} \ln \left (c^{2} x^{4}+1\right )}{6 c^{4}}+\frac {a b \,x^{8} \arctan \left (c \,x^{2}\right )}{4}-\frac {a b \,x^{6}}{12 c}+\frac {a b \,x^{2}}{4 c^{3}}-\frac {a b \arctan \left (c \,x^{2}\right )}{4 c^{4}}\) | \(151\) |
parts | \(\frac {a^{2} x^{8}}{8}+\frac {b^{2} x^{8} \arctan \left (c \,x^{2}\right )^{2}}{8}-\frac {b^{2} \arctan \left (c \,x^{2}\right ) x^{6}}{12 c}+\frac {b^{2} x^{2} \arctan \left (c \,x^{2}\right )}{4 c^{3}}-\frac {b^{2} \arctan \left (c \,x^{2}\right )^{2}}{8 c^{4}}+\frac {b^{2} x^{4}}{24 c^{2}}-\frac {b^{2} \ln \left (c^{2} x^{4}+1\right )}{6 c^{4}}+\frac {a b \,x^{8} \arctan \left (c \,x^{2}\right )}{4}-\frac {a b \,x^{6}}{12 c}+\frac {a b \,x^{2}}{4 c^{3}}-\frac {a b \arctan \left (c \,x^{2}\right )}{4 c^{4}}\) | \(151\) |
parallelrisch | \(-\frac {-3 b^{2} \arctan \left (c \,x^{2}\right )^{2} x^{8} c^{4}-6 a b \arctan \left (c \,x^{2}\right ) x^{8} c^{4}-3 c^{4} a^{2} x^{8}+2 b^{2} \arctan \left (c \,x^{2}\right ) x^{6} c^{3}+2 a b \,c^{3} x^{6}-x^{4} b^{2} c^{2}-6 b^{2} \arctan \left (c \,x^{2}\right ) x^{2} c -6 a b c \,x^{2}+3 b^{2} \arctan \left (c \,x^{2}\right )^{2}+4 b^{2} \ln \left (c^{2} x^{4}+1\right )+6 a b \arctan \left (c \,x^{2}\right )+b^{2}}{24 c^{4}}\) | \(155\) |
risch | \(-\frac {b^{2} \left (c^{4} x^{8}-1\right ) \ln \left (i c \,x^{2}+1\right )^{2}}{32 c^{4}}-\frac {i b \left (6 a \,c^{4} x^{8}+3 i b \,c^{4} x^{8} \ln \left (-i c \,x^{2}+1\right )-2 b \,c^{3} x^{6}+6 b c \,x^{2}-3 i b \ln \left (-i c \,x^{2}+1\right )\right ) \ln \left (i c \,x^{2}+1\right )}{48 c^{4}}-\frac {b^{2} x^{8} \ln \left (-i c \,x^{2}+1\right )^{2}}{32}+\frac {i a b \,x^{8} \ln \left (-i c \,x^{2}+1\right )}{8}+\frac {a^{2} x^{8}}{8}-\frac {i b^{2} x^{6} \ln \left (-i c \,x^{2}+1\right )}{24 c}-\frac {a b \,x^{6}}{12 c}+\frac {b^{2} x^{4}}{24 c^{2}}+\frac {i b^{2} x^{2} \ln \left (-i c \,x^{2}+1\right )}{8 c^{3}}+\frac {a b \,x^{2}}{4 c^{3}}+\frac {b^{2} \ln \left (-i c \,x^{2}+1\right )^{2}}{32 c^{4}}-\frac {a b \arctan \left (c \,x^{2}\right )}{4 c^{4}}-\frac {b^{2} \ln \left (c^{2} x^{4}+1\right )}{6 c^{4}}\) | \(280\) |
[In]
[Out]
none
Time = 0.25 (sec) , antiderivative size = 137, normalized size of antiderivative = 1.10 \[ \int x^7 \left (a+b \arctan \left (c x^2\right )\right )^2 \, dx=\frac {3 \, a^{2} c^{4} x^{8} - 2 \, a b c^{3} x^{6} + b^{2} c^{2} x^{4} + 6 \, a b c x^{2} + 3 \, {\left (b^{2} c^{4} x^{8} - b^{2}\right )} \arctan \left (c x^{2}\right )^{2} + 6 \, a b \arctan \left (\frac {1}{c x^{2}}\right ) - 4 \, b^{2} \log \left (c^{2} x^{4} + 1\right ) + 2 \, {\left (3 \, a b c^{4} x^{8} - b^{2} c^{3} x^{6} + 3 \, b^{2} c x^{2}\right )} \arctan \left (c x^{2}\right )}{24 \, c^{4}} \]
[In]
[Out]
Time = 44.49 (sec) , antiderivative size = 199, normalized size of antiderivative = 1.60 \[ \int x^7 \left (a+b \arctan \left (c x^2\right )\right )^2 \, dx=\begin {cases} \frac {a^{2} x^{8}}{8} + \frac {a b x^{8} \operatorname {atan}{\left (c x^{2} \right )}}{4} - \frac {a b x^{6}}{12 c} + \frac {a b x^{2}}{4 c^{3}} - \frac {a b \operatorname {atan}{\left (c x^{2} \right )}}{4 c^{4}} + \frac {b^{2} x^{8} \operatorname {atan}^{2}{\left (c x^{2} \right )}}{8} - \frac {b^{2} x^{6} \operatorname {atan}{\left (c x^{2} \right )}}{12 c} + \frac {b^{2} x^{4}}{24 c^{2}} + \frac {b^{2} x^{2} \operatorname {atan}{\left (c x^{2} \right )}}{4 c^{3}} - \frac {b^{2} \sqrt {- \frac {1}{c^{2}}} \operatorname {atan}{\left (c x^{2} \right )}}{3 c^{3}} - \frac {b^{2} \log {\left (x^{2} + \sqrt {- \frac {1}{c^{2}}} \right )}}{3 c^{4}} - \frac {b^{2} \operatorname {atan}^{2}{\left (c x^{2} \right )}}{8 c^{4}} & \text {for}\: c \neq 0 \\\frac {a^{2} x^{8}}{8} & \text {otherwise} \end {cases} \]
[In]
[Out]
none
Time = 0.38 (sec) , antiderivative size = 169, normalized size of antiderivative = 1.36 \[ \int x^7 \left (a+b \arctan \left (c x^2\right )\right )^2 \, dx=\frac {1}{8} \, b^{2} x^{8} \arctan \left (c x^{2}\right )^{2} + \frac {1}{8} \, a^{2} x^{8} + \frac {1}{12} \, {\left (3 \, x^{8} \arctan \left (c x^{2}\right ) - c {\left (\frac {c^{2} x^{6} - 3 \, x^{2}}{c^{4}} + \frac {3 \, \arctan \left (c x^{2}\right )}{c^{5}}\right )}\right )} a b - \frac {1}{24} \, {\left (2 \, c {\left (\frac {c^{2} x^{6} - 3 \, x^{2}}{c^{4}} + \frac {3 \, \arctan \left (c x^{2}\right )}{c^{5}}\right )} \arctan \left (c x^{2}\right ) - \frac {c^{2} x^{4} + 3 \, \arctan \left (c x^{2}\right )^{2} - 3 \, \log \left (12 \, c^{7} x^{4} + 12 \, c^{5}\right ) - \log \left (c^{2} x^{4} + 1\right )}{c^{4}}\right )} b^{2} \]
[In]
[Out]
none
Time = 0.28 (sec) , antiderivative size = 145, normalized size of antiderivative = 1.17 \[ \int x^7 \left (a+b \arctan \left (c x^2\right )\right )^2 \, dx=\frac {3 \, a^{2} c x^{8} + 2 \, {\left (3 \, c x^{8} \arctan \left (c x^{2}\right ) - \frac {3 \, \arctan \left (c x^{2}\right )}{c^{3}} - \frac {c^{9} x^{6} - 3 \, c^{7} x^{2}}{c^{9}}\right )} a b + {\left (3 \, c x^{8} \arctan \left (c x^{2}\right )^{2} - \frac {2 \, c^{3} x^{6} \arctan \left (c x^{2}\right ) - c^{2} x^{4} - 6 \, c x^{2} \arctan \left (c x^{2}\right ) + 3 \, \arctan \left (c x^{2}\right )^{2} + 4 \, \log \left (c^{2} x^{4} + 1\right )}{c^{3}}\right )} b^{2}}{24 \, c} \]
[In]
[Out]
Time = 1.17 (sec) , antiderivative size = 150, normalized size of antiderivative = 1.21 \[ \int x^7 \left (a+b \arctan \left (c x^2\right )\right )^2 \, dx=\frac {a^2\,x^8}{8}-\frac {b^2\,{\mathrm {atan}\left (c\,x^2\right )}^2}{8\,c^4}+\frac {b^2\,x^8\,{\mathrm {atan}\left (c\,x^2\right )}^2}{8}-\frac {b^2\,\ln \left (c^2\,x^4+1\right )}{6\,c^4}+\frac {b^2\,x^4}{24\,c^2}+\frac {b^2\,x^2\,\mathrm {atan}\left (c\,x^2\right )}{4\,c^3}-\frac {b^2\,x^6\,\mathrm {atan}\left (c\,x^2\right )}{12\,c}+\frac {a\,b\,x^2}{4\,c^3}-\frac {a\,b\,x^6}{12\,c}-\frac {a\,b\,\mathrm {atan}\left (c\,x^2\right )}{4\,c^4}+\frac {a\,b\,x^8\,\mathrm {atan}\left (c\,x^2\right )}{4} \]
[In]
[Out]